В параллелограмме ABCD {"color":"#202335","fontFamily":"stix","language":"ru"}угол BAC {"color":"#202335","fontFamily":"stix","language":"ru"}вдвое больше угла CAD{"color":"#202335","fontFamily":"stix","language":"ru"}. Биссектриса угла BAC{"color":"#202335","fontFamily":"stix","language":"ru"}
пересекает отрезок ВС {"color":"#202335","fontFamily":"stix","language":"ru"}в точке L{"color":"#202335","fontFamily":"stix","language":"ru"}. На продолжении стороны CD {"color":"#202335","fontFamily":"stix","language":"ru"}за точку D {"color":"#202335","fontFamily":"stix","language":"ru"}выбрана
такая точка Е{"color":"#202335","fontFamily":"stix","language":"ru"}, что AE = CE.{"color":"#202335","fontFamily":"stix","language":"ru"}
a) Докажите, что AL : AC= AB: BC.{"color":"#202335","fontFamily":"stix","language":"ru"}
б) Найдите EL{"color":"#202335","fontFamily":"stix","language":"ru"}, если AC = 21, tg BCA = 0,4.{"color":"#202335","fontFamily":"stix","language":"ru"}
