В треугольнике ABC{"color":"#202335","fontFamily":"stix","language":"ru"} AВ=BC,{"color":"#202335","fontFamily":"stix","language":"ru"} а высота AH{"color":"#202335","fontFamily":"stix","language":"ru"} делит сторону BC{"color":"#202335","fontFamily":"stix","language":"ru"} на отрезки BH=64{"color":"#202335","fontFamily":"stix","language":"ru"} и CH=16.{"color":"#202335","fontFamily":"stix","language":"ru"} Найдите cosB.{"color":"#202335","fontFamily":"stix","language":"ru"}
