В основании пирамиды SABCD{"color":"#202335","fontFamily":"stix","language":"ru"} лежит ромб ABCD{"color":"#202335","fontFamily":"stix","language":"ru"}, сторона которого равна 7{"color":"#202335","fontFamily":"stix","language":"ru"}, а угол при вершине A{"color":"#202335","fontFamily":"stix","language":"ru"} равен 60°{"color":"#202335","fontFamily":"stix","language":"ru"}. Известно, что SA=13{"color":"#202335","fontFamily":"stix","language":"ru"}, SC=22{"color":"#202335","fontFamily":"stix","language":"ru"} и SB=SD{"color":"#202335","fontFamily":"stix","language":"ru"}.
а) Докажите, что SC{"color":"#202335","fontFamily":"stix","language":"ru"} – высота пирамиды.
б) Найдите угол между плоскостью ASC{"color":"#202335","fontFamily":"stix","language":"ru"} и ребром SB{"color":"#202335","fontFamily":"stix","language":"ru"}.